Sunday, November 22, 2020

Free NECO Physics Paper II Obj & Essay - ZAZZAFA TV



Free NECO Physics Paper II Obj & Essay - ZAZZAFA TV

A. 2020 NECO PHYSICS (OBJECTIVES) ANSWERS:

1-10: BCBDBDCDCD
11-20: DACBEBABDE
21-30: CDDDABBBAC 
21-30: CDDDABBBAC
31-40: CDAEBBCCDC 
41-50: BEEBDBAEEC
51-60: DDCDADDEBD


B. 2020 NECO PHYSICS (ESSAY) ANSWERS:

(1ai)

[Choose ANY ONE]

-Printer

-Photocopy machine

-Label maker

-Document scanner


(1aii)

Sterilizer


(1b)

Draw the diagram.


(1c)

I = 1.26A

t = 4800s

m = ?

Z = 3.3×10^-⁴gc-¹

m = ZIt

m = 3.3×10^-⁴×1.26×4800

m = 1.996g



=============================================

(3a)
Velocity is defined as the rate of change of distance moved in a specific direction or the rate of change of displacement.

(3b)
U = 0m/a
V = 20ms-¹
t1 = 20s
t2 = 30s
t3 = 10s

Draw the diagram



=============================================

(5a)

[Choose ONLY ONE]

-They are both scalar quantity.

-They are both connected with work.


(5b)

R0 = 25ohms

R100 = 100ohms

R = ?

Tita = 67°c

Tita= Rtita-R0/R100-25 × 100

67 = R - 25/100 - 25 × 100

67 = (R0 - 25)/75 × 100

R0 - 25 = 67 × 75/100

Rtita - 25 = 50.25

Rtita = 50.25+25

Rtita = 75.25ohms


============================================

(9a)
It simply means that the ratio of resistance and impedance is 1 and the maximum power is obtained in such circuit.

(9b)
V² = Vr² + Vc²
15² = 12² + Vc²
225 - 144 = Vc²
V = √81
Vc = 9


============================================

(10a)
(i) Weight
(ii) Upthrust.
(iii) Viscous force.

(10b)
Both viscous force and upthrust acts in upward direction while weight act downward in order to balance the force

============================================

(11)


(11i)


4 A 12 1

He + Be --> X + Y + Z

2 A B C


A = 9

B = 6

C = 1


(11ii)

Z = 0

e ie Beta particles.

-1


(11iii)

Nuclear fusion

W = v + u



============================================

(12a)

(i) Friction.

(ii) Upthrust.


(12aii)

(i) Force causes motion

(ii) Force causes stress/strain


(12b)

Draw the diagram [https://i.imgur.com/j8jNZmi.jpg]


(12c)

Draw the diagram [https://i.imgur.com/j8jNZmi.jpg]

(i) Taking moment about pivot

CW moment = ACW moment

36×25 = X×15

X = 36×25/15 = 60g


(ii)

Draw the diagram[https://i.imgur.com/j8jNZmi.jpg]

60 × X = 36 × (30 - X)

60X = 1080 - 36x

96X = 1080

X = 1080/96 = 11.25

Distance = 11.25 from the zero end.


============================================

(13ai)

(i) Dew

(ii) Mist


(13aii)

(i) Both require the supply of heat.

(ii) Vapour is expelled when both processes occur.


(13b)

An object initially at a height, say H has a tiny potential energy. As it falls and now at a height say h, the potential energy reduces and kinetic energy increases. The kinetic energy because it is equal to the P.E at height H when the object just strikes the ground.

NB: At any point, mechanical energy is conserved.


(13ci)

Given V.R = 5, Load L = 500N

Workdone against friction

= Total workdone - work output by system.

= 7200 - (500 × 12)

= 7200 - 6000

= 1200J


(13cii)

Efficiency = work output/work input × 100%

= 6000/7200 × 100%

= 83.33%



============================================


(14a)

Given y = Asin2pie(t/T - x/lander)


(i)

T represents period.

Lander represents wavelength.


(ii)

T = 2pie/w

T = 1/f


(14bi)

(i) Microscope.

(ii) Telescope.


(14bii)

Refraction involves two media, while reflection involves one medium.


(14ci)

Frequenxy of wave f = v/lander

= 0.6/0.04 = 1.5 Hertz


(14cii)

Refractive index of water = speed in deep water/speed in shallow water.

= 0.8/0.6 = 4/3


============================================

(15a)

The potential difference between any two points in an electric field is defined as the work done in moving a positive charge of 1 coulomb from one point in the electric field to another.


(15b)

Diagram [CHECK THE DIAGRAM BELOW]


(15c)

Given: Power p = 1200w, Voltage v = 220v

(i)Resistance, R = v²/p = 220×220/1200 = 40.3ohms


(ii)

Energy consumed by one heater = Power × time

= 1200 × 5

= 6000watt-hours

= 6kWh

Energy consumed by 5 heaters = 5 × 6 kWh

= 30kwh

Cost = 30 × 4

= #1,020.00









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